Algorithm Question

Sum of the first nth term of Series

Task:

Your task is to write a function which returns the sum of following series upto nth term(parameter).

Series: 1 + 1/4 + 1/7 + 1/10 + 1/13 + 1/16 +..

Rules:

• You need to round the answer to 2 decimal places and return it as String.
• If the given value is 0 then it should return 0.00
• You will only be given Natural Numbers as arguments.

Examples:(Input → Output)

1 --> 1 --> "1.00"
2 --> 1 + 1/4 --> "1.25"
5 --> 1 + 1/4 + 1/7 + 1/10 + 1/13 --> "1.57"

Answer

1 --> 1 --> "1.00"
2 --> 1 + 1/4 --> "1.25"
5 --> 1 + 1/4 + 1/7 + 1/10 + 1/13 --> "1.57"

1 --> 1 --> "1.00"
2 --> 1 + 1/4 --> "1.25"
5 --> 1 + 1/4 + 1/(4+3*1) + 1/(4+(3*2)) + 1/(4+(3*3)) --> "1.57"


function series(n){
  var values = [];
  var sum = 0;
  if(n != 0){
    if(n == 1){
    sum = 1;  
    }else{
     for(let i=1; i<=n; i++){
       if(i == 1){
         sum = 1;
         values.push("1")
       }else{
         if(i == 2){
           sum += (1/4)
           values.push("1/"+4)
         }else{
           sum += (1/(4+(3*(i-2))))
           values.push("1/"+(4+(3*(i-2))))
         }
       }
     }
    }
  }
  console.log(values,'\n',"sum = "+sum.toFixed(2))
}
series(2);